Convert Sorted Array to Binary Search Tree
Problem Description
Given an integer array nums where the elements are sorted in ascending order, convert it to a height-balanced binary search tree.
Example 1:
Input: nums = [-10,-3,0,5,9] Output: [0,-3,9,-10,null,5] Explanation: [0,-10,5,null,-3,null,9] is also accepted:![]()
Example 2:
Input: nums = [1,3] Output: [3,1] Explanation: [1,null,3] and [3,1] are both height-balanced BSTs.
Constraints:
1 <= nums.length <= 104-104 <= nums[i] <= 104numsis sorted in a strictly increasing order.
Solution (Go)
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func sortedArrayToBST(nums []int) *TreeNode {
if len(nums) == 0 {
return nil
}
mid := len(nums) / 2
root := &TreeNode{Val: nums[mid]}
root.Left = sortedArrayToBST(nums[:mid])
root.Right = sortedArrayToBST(nums[mid+1:])
return root
}