Fizz Buzz

Problem Description

Given an integer n, return a string array answer (1-indexed) where:

• answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
• answer[i] == "Fizz" if i is divisible by 3.
• answer[i] == "Buzz" if i is divisible by 5.
• answer[i] == i (as a string) if none of the above conditions are true.

Example 1:

Input: n = 3
Output: ["1","2","Fizz"]

Example 2:

Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]

Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

Constraints:

• 1 <= n <= 104

Solution (Go)

func fizzBuzz(n int) []string {
	arr := make([]string, n)
	for i := 1; i <= n; i++ {
		if i%3 == 0 && i%5 == 0 {
			arr[i-1] = "FizzBuzz"
		} else if i%3 == 0 {
			arr[i-1] = "Fizz"
		} else if i%5 == 0 {
			arr[i-1] = "Buzz"
		} else {
			arr[i-1] = fmt.Sprintf("%d", i)
		}
	}
	return arr
}